TS EAMCET · Physics · Oscillations
The time period of a particle in simple harmonic motion is \(8 \mathrm{~s}\). At \(t=0\), it is at the mean position. The ratio of the distances travelled by it in the first and second seconds is
- A \(\frac{1}{2}\)
- B \(\frac{1}{\sqrt{2}}\)
- C \(\frac{1}{\sqrt{2}-1}\)
- D \(\frac{1}{\sqrt{3}}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{\sqrt{2}-1}\)
Step-by-step Solution
Detailed explanation
Distance \(y_1=A \sin \frac{2 \pi}{8} \times 1=\frac{A}{\sqrt{2}}\) and \(y_2=A-\frac{A}{\sqrt{2}}\) The ratio of the distances travelled by it in the first and seconds. \(\frac{y_1}{y_2}=\frac{1}{\sqrt{2}-1}\)
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