TS EAMCET · Physics · Current Electricity
The sensitivity of a galvanometer is 60 division/A. When a shunt is used, its sensitivity becomes 10 division/A. If the galvanometer is of resistance \(20 \Omega\), the value of shunt used is
- A \(4 \Omega\)
- B \(5 \Omega\)
- C \(20 \Omega\)
- D \(2 \Omega\)
Answer & Solution
Correct Answer
(A) \(4 \Omega\)
Step-by-step Solution
Detailed explanation
We have, \(i_g=i\left(\frac{S}{G+S}\right)\) where \(i=\) total current Sensitivity \(=\frac{i_g}{i}=\frac{10}{60}=\frac{1}{6}\) \(\therefore \quad \frac{1}{6}=\frac{S}{G+S}\)…
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