TS EAMCET · Physics · Rotational Motion
A thin wiform circular disc of mass \(M\) and radius \(R\) is rotating in a horizontal plane about an axis passing through its centre and perpendicular to its plane with an angular velocity \(\omega\). Another disc of same thickness and radius but of mass \(\frac{1}{8} M\) is placed gently on the first disc coaxially. The angular velocity of the system is now
- A \(\frac{8}{9} w\)
- B \(\frac{5}{9} w\)
- C \(\frac{1}{3} w\)
- D \(\frac{2}{9} w\)
Answer & Solution
Correct Answer
(A) \(\frac{8}{9} w\)
Step-by-step Solution
Detailed explanation
Given, mass of first circular disc \(\left(m_1\right)=M\) Radius of first circular disc \(\left(r_1\right)=R\) Mass of second circular disc \(\left(m_2\right)=\frac{1}{8} M\) For first disc,…
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