TS EAMCET · Physics · Alternating Current
A coil has a resistance of \(30 \Omega\) and an inductive reactance of \(20 \Omega\) at \(50 \mathrm{~Hz}\) frequency. If an AC source of \(200 \mathrm{~V}\), \(100 \mathrm{~Hz}\) is connected across the coil, the current in the coil is
- A \(2 \mathrm{~A}\)
- B \(\frac{20}{\sqrt{13}} \mathrm{~A}\)
- C \(4 \mathrm{~A}\)
- D \(8 \mathrm{~A}\)
Answer & Solution
Correct Answer
(C) \(4 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Inductive reactance, \(\mathrm{X}_{\mathrm{L}}=\omega \mathrm{L} \therefore 20=2 \pi\) (50) L...(1) When AC source of \(200 \mathrm{~V}, 100 \mathrm{~Hz}\) is connected across the coil then…
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