TS EAMCET · Physics · Thermal Properties of Matter
The temperature difference between the ends of two cylindrical rods \(A\) and \(B\) of the same material is \(2: 3\). In steady state the ratio of the rates of flow of heat through the rods \(A\) and \(B\) is \(5: 9\). If the radii of the rods \(A\) and \(B\) are in the ratio \(1: 2\), then the ratio of lengths of the rods \(A\) and \(B\) is
- A \(2: 7\)
- B \(3: 7\)
- C \(2: 5\)
- D \(3: 10\)
Answer & Solution
Correct Answer
(D) \(3: 10\)
Step-by-step Solution
Detailed explanation
For two cylindrical rods A and B, \(\theta_1: \theta_2=2: 3, H_1: H_2=5: 9, r_1: r_2=1: 2\) \(\therefore \quad\) At steady state, \(\mathrm{H}=\frac{\mathbb{k}\left(\pi \mathrm{r}^2\right)^8}{\ell} \propto \frac{\mathrm{r}^2 \theta}{\ell}\)…
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