TS EAMCET · Physics · Dual Nature of Matter
An isolated lead ball is charged upon continuous irradiation by EM radiation of wavelength, \(\lambda=221 \mathrm{~nm}\). The maximum potential attained by the lead ball, if its work function is \(4.14 \mathrm{eV}\) is (take, \(h=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}\), \(c=3 \times 10^8 \mathrm{~m} / \mathrm{s}, e=1.6 \times 10^{-19} \mathrm{C}\) )
- A \(1.49 \mathrm{~V}\)
- B \(2.67 \mathrm{~V}\)
- C \(3.14 \mathrm{~V}\)
- D \(0.51 \mathrm{~V}\)
Answer & Solution
Correct Answer
(A) \(1.49 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Given, \(\lambda=2.21 \times 10^{-7} \mathrm{~m}\) So, energy of imparted by radiation in the lead ball,…
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