TS EAMCET · Physics · Magnetic Effects of Current
A current of \(1 \mathrm{~A}\) is flowing along the sides of an equilateral triangle of side \(4.5 \times 10^{-2} \mathrm{~m}\). The magnetic field at the centroid of the triangle is \(\left(\mu_0=4 \pi \times 10^{-7} \mathrm{H} / \mathrm{m}\right)\)
- A \(4 \times 10^{-5} \mathrm{~T}\)
- B \(2 \times 10^{-5} \mathrm{~T}\)
- C \(4 \times 10^{-4} \mathrm{~T}\)
- D \(2 \times 10^{-4} \mathrm{~T}\)
Answer & Solution
Correct Answer
(B) \(2 \times 10^{-5} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
Let the centroid of the triangle is \(O\), magnetic field due to side \(A B\) \[ B_1=\frac{\mu_0}{4 \pi} \cdot \frac{i}{r}\left(\sin \phi_1+\sin \phi_2\right) \] where, \(r\) is perpendicular distance of \(A B\) from centroid \(O\). The magnetic field due to each side is same in…
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