TS EAMCET · Physics · Alternating Current

$A B C D$ is a rectangular loop made of uniform wire. If $A D = B C = 2 cm,$ what is the magnetic force per unit length acting on wire $D C$ due to wire $A B$ if ammeter reads $20 A .$ (The length of $A B$ and $D C$ are large in comparison with other two sides)

A $10^{- 1} N m^{- 1}$
B $10^{- 2} N m^{- 1}$
C $10^{- 3} N m^{- 1}$
D $10^{- 4} N m^{- 1}$

Verified Solution

Answer & Solution

Correct Answer

(C) $10^{- 3} N m^{- 1}$

Step-by-step Solution

Detailed explanation

The current will divide into two equal parts say each 10 A, then recall the formula of force per unit length in terms of current in each wire is, FL=μ0i1i22πr, given, i1=i2=10 A and the value is, r=2×10-2 cm, now put the values in the above formula,…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From TS EAMCET

Explore more questions on app

ABCD is a rectangular loop made of uniform wire. If AD=BC=2 cm, what is the magnetic force per unit length acting on wire DC due to wire AB if ammeter reads 20 A. (The length of AB and DC are large in comparison with other two sides)

Step-by-step Solution

$A B C D$ is a rectangular loop made of uniform wire. If $A D = B C = 2 cm,$ what is the magnetic force per unit length acting on wire $D C$ due to wire $A B$ if ammeter reads $20 A .$ (The length of $A B$ and $D C$ are large in comparison with other two sides)