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TS EAMCET · Physics · Rotational Motion

A solid sphere of mass \(5 \mathrm{~kg}\) rolls on a plane surfaces. Find its kinetic energy at an instant when its centre moves with speed \(4 \mathrm{~m} / \mathrm{s}\).

  1. A \(56 \mathrm{~J}\)
  2. B \(45 \mathrm{~J}\)
  3. C \(75 \mathrm{~J}\)
  4. D \(105 \mathrm{~J}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(56 \mathrm{~J}\)

Step-by-step Solution

Detailed explanation

As we know, the rotational kinetic energy of a body is given by, \[ \mathrm{KE}=\frac{1}{2} m v^2\left[1+\frac{k^2}{R^2}\right] \] where,\(k=\) radius of gyration Given, \(m=5 \mathrm{~kg}, v=4 \mathrm{~m} / \mathrm{s}\) and \(k=\sqrt{\frac{2}{5}} R\) Hence,…
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