TS EAMCET · Physics · Mechanical Properties of Fluids
The rate of steady volume flow of water through a capillary tube of length \(l\) and radius \(r\), under a pressure difference of \(p\) is \(V\). This tube is connected with another tube of the same length but half the radius, in series. Then, the rate of steady volume flow through them is (The pressure difference across the combination is \(p\). )
- A \(\frac{V}{16}\)
- B \(\frac{V}{17}\)
- C \(\frac{16 \mathrm{~V}}{17}\)
- D \(\frac{17 \mathrm{~V}}{16}\)
Answer & Solution
Correct Answer
(B) \(\frac{V}{17}\)
Step-by-step Solution
Detailed explanation
The rate of flow of water inside a capillary, \(V=\frac{\pi p r^4}{8 n l^{\prime}}\) Pressure difference, \(p=\frac{V(8 n l)}{\pi r^4}\) In series combination, \(p=p_1+p_2\) where, \(p_1\) and \(p_2\) are the pressure difference in the two tubes.…
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