TS EAMCET · Physics · Communication System
A TV transmission tower of height \(h\) covers a range of distance \(d\). By how much will be the range change, if the height is increased to \(3 / 2 \mathrm{~h} ?\)
- A \(\sqrt{\frac{3}{2}} d\)
- B \(\left(\sqrt{\frac{3}{2}}-1\right) d\)
- C \(\left(\sqrt{\frac{3}{2}}+1\right) d\)
- D d
Answer & Solution
Correct Answer
(B) \(\left(\sqrt{\frac{3}{2}}-1\right) d\)
Step-by-step Solution
Detailed explanation
If a tower of height \(h\) covers a range of distance \(d\), then \(d=\sqrt{2 h R}\). where, \(R\) is the radius of the earth. when \(h^{\prime}=\frac{3}{2} h\), then \(d^{\prime}=\sqrt{2 h^{\prime} R^{\prime}}\) \(=\sqrt{2 \times \frac{3}{2} h R}=\sqrt{\frac{3}{2} d}\)…
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