TS EAMCET · Physics · Ray Optics
Consider a light source placed at a distance of \(1.5 \mathrm{~m}\) along the axis facing the convex side of a spherical mirror of radius of curvature \(1 \mathrm{~m}\). The position \(\left(s^{\prime}\right)\), natwre and magnification (m) of the image are
- A \(s^{\prime}=0.375 \mathrm{~m}\), virtual, upright, \(m=0.25\)
- B \(s^{\prime}=0.375 \mathrm{~m}\), real, inverted, \(m=025\)
- C \(s^{\prime}=3.75 \mathrm{~m}\), virtual, inverted, \(m=2.5\)
- D \(s^{\prime}=3.75 \mathrm{~m}\), real, upright, \(m=2.5\)
Answer & Solution
Correct Answer
(A) \(s^{\prime}=0.375 \mathrm{~m}\), virtual, upright, \(m=0.25\)
Step-by-step Solution
Detailed explanation
Given, Distance of light source \((u)=-1.5 \mathrm{~m}=-\frac{-3}{2} \mathrm{~m}\) Radius of curvature of mirror \((R)=1 \mathrm{~m}\) of We know that, \[ \frac{1}{f}=\frac{1}{V}+\frac{1}{u} \quad\left[\because f=\frac{R}{2}\right] \]…
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