TS EAMCET · Physics · Ray Optics
A compound microscope has an objective of focal length 1.25 cm and an eyepiece of focal length 5 cm separated by a distance of 7.5 cm. The total magnification produced by the microscope when the final image forms at infinity is
- A \(6.25\)
- B \(30\)
- C \(120\)
- D \(72.5\)
Answer & Solution
Correct Answer
(B) \(30\)
Step-by-step Solution
Detailed explanation
\(M = \left(\frac{L}{f_o}\right) \left(\frac{D}{f_e}\right)\) \(M = \left(\frac{7.5 \text{ cm}}{1.25 \text{ cm}}\right) \left(\frac{25 \text{ cm}}{5 \text{ cm}}\right)\) \(M = (6) \times (5)\) \(M = 30\)
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