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TS EAMCET · Physics · Capacitance

The potential difference between two parallel plates is \(10^4 \mathrm{~V}\). If the plates are separated by \(0.5 \mathrm{~cm}\), the force on an electron between the plates is

  1. A \(32 \times 10^{-13} \mathrm{~N}\)
  2. B \(0.32 \times 10^{-13} \mathrm{~N}\)
  3. C \(0.032 \times 10^{-13} \mathrm{~N}\)
  4. D \(3.2 \times 10^{-13} \mathrm{~N}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(3.2 \times 10^{-13} \mathrm{~N}\)

Step-by-step Solution

Detailed explanation

The force \(F=\frac{e V}{d}\) \(=\frac{1.6 \times 10^{-19} \times 10^4}{0.5 \times 10^{-2}}\) \(=3.2 \times 10^{-13} \mathrm{~N}\)
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