TS EAMCET · Physics · Electromagnetic Waves
If a plane electromagnetic wave has electric field oscillations of frequency \(3 \mathrm{GHz}\) then the wavelength of the wave is (speed of light in vacuum \(=3 \times 10^8 \mathrm{~ms}^{-1}\) )
- A \(0.1m\)
- B \(0.2m\)
- C \(100m\)
- D \(0.003m\)
Answer & Solution
Correct Answer
(C) \(100m\)
Step-by-step Solution
Detailed explanation
Frequency of osciliations, \(\mathrm{f}=3 \mathrm{GHz}=3 \times 10^6 \mathrm{~Hz}\) Wavelength of wave, \(\lambda=\frac{\mathrm{c}}{\mathrm{f}}\) \(\begin{aligned} & =\frac{3 \times 10^8}{3 \times 10^6} \\ & =100 \mathrm{~m} \end{aligned}\)
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