TS EAMCET · Physics · Magnetic Effects of Current
A very long wire carrying a current \(4 \sqrt{2} \mathrm{~A}\) is bent at a right angles. The magnitude of magnetic field ( \(|\mathbf{B}|)\) at a point \(P\) lying on a line perpendicular to the bent wire at a distance, \(d=20 \mathrm{~cm}\) from the point of the bending will be (Let \(\mu_0=4 \pi \times 10^{-7} \mathrm{H} / \mathrm{m}\) )

- A \(1 \mu \top\)
- B \(0.8 \mu \mathrm{T}\)
- C \(2 \mu \top\)
- D \(4 \mu \mathrm{T}\)
Answer & Solution
Correct Answer
(D) \(4 \mu \mathrm{T}\)
Step-by-step Solution
Detailed explanation
Given, \(\mu_0=4 \pi \times 10^{-7} \mathrm{H} / \mathrm{m}\) distance, \(\quad d=20 \mathrm{~cm}=0.2 \mathrm{~m}\) and current, \(I=4 \sqrt{2} \mathrm{~A}\) \(\therefore\) Magnetic field at a point \(P\) due to current carrying wire 1 ,…
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