TS EAMCET · Physics · Electromagnetic Waves
If the amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is 270 nT , the amplitude of the electric field part of the wave is
- A \(90 \mathrm{NC}^{-1}\)
- B \(81 \mathrm{NC}^{-1}\)
- C \(9 \mathrm{NC}^{-1}\)
- D \(30 \mathrm{NC}^{-1}\)
Answer & Solution
Correct Answer
(B) \(81 \mathrm{NC}^{-1}\)
Step-by-step Solution
Detailed explanation
Speed of light in vacuum \(C=\frac{E_0}{B_0} \Rightarrow\) Amplitude of the electric field \(\mathrm{E}_{\mathrm{o}}=\mathrm{CB}_0=3 \times 10^8 \times 270 \times 10^{-9}\) \(=81 \mathrm{NC}^{-1}\)
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