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TS EAMCET · Physics · Center of Mass Momentum and Collision

The balls \(A, B\) and \(C\) of masses \(50 \mathrm{~g}, 100 \mathrm{~g}\) and \(150 \mathrm{~g}\), respectively are placed at the vertices of an equilateral triangle. The length of each side is \(1 \mathrm{~m}\). If \(A\) is placed at \((0,0)\) and \(B\) is placed at \((1,0) \mathrm{m}\), find the coordinates \((x, y)\) for the centre of mass of this system of the balls

  1. A \(\left(\frac{7}{12}, \sqrt{\frac{3}{4}}\right) \mathrm{m}\)
  2. B \(\left(\frac{5}{18}, \sqrt{\frac{1}{4}}\right) \mathrm{m}\)
  3. C \(\left(\frac{7}{12}, \sqrt{\frac{3}{2}}\right) \mathrm{m}\)
  4. D None of these.
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Answer & Solution

Correct Answer

(D) None of these.

Step-by-step Solution

Detailed explanation

Given, \( \begin{aligned} & \text { mass of ball } A_1 m_1=50 \mathrm{~g} \\ & \text { mass of ball } B, m_2=100 \mathrm{~g} \\ & \text { mass of ball } \mathrm{C}, m_3=150 \mathrm{~g} \end{aligned} \) and length of each side of triangle \(=1 \mathrm{~m}\)…
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