TS EAMCET · Physics · Mechanical Properties of Fluids
A shower head has 25 circular openings, each with radius \(1 \mathrm{~mm}\). The shower head is connected to a pipe with radius \(2 \mathrm{~cm}\). If the speed of the water in the pipe is \(25 \mathrm{~cm} / \mathrm{s}\). What is its speed as it exits the shower head openings?
- A \(1 \mathrm{~m} / \mathrm{s}\)
- B \(2 \mathrm{~m} / \mathrm{s}\)
- C \(4 \mathrm{~m} / \mathrm{s}\)
- D \(5 \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(C) \(4 \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
Radius of each circular opening, \[ \begin{aligned} r_1 & =1 \mathrm{~mm} \\ & =10^{-3} \mathrm{~m} \end{aligned} \] \(\therefore\) Cross-sectional area of each opening, \[ A_1=\pi r_1^2=\pi \times 10^{-6} \mathrm{~m}^2 \] Radius of the pipe,…
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