TS EAMCET · Physics · Magnetic Effects of Current
The magnetic field at a perpendicular distance of one metre from a wire carrying current of \(1 \mathrm{~A}\) is
- A \(2 \times 10^{-7} \mathrm{~T}\)
- B \(2 \times 10^{-8} \mathrm{~T}\)
- C \(2 \times 10^{-6} \mathrm{~T}\)
- D \(2 \times 10^{-9} \mathrm{~T}\)
Answer & Solution
Correct Answer
(A) \(2 \times 10^{-7} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
Magnetic field due to wire is given by, \[ \begin{aligned} & B=\frac{\mu_0 i}{2 \pi r} \\ & B=\frac{4 \pi \times 10^{-7} \times 1}{2 \pi \times 1}=2 \times 10^{-7} T \end{aligned} \]
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