TS EAMCET · Physics · Laws of Motion
Consider a system of two masses and a pulley shown in the figure. The coefficient of friction between the two blocks and also between block and table is 0.1 . Find the force \(F\), that must be given to the \(0.8 \mathrm{~kg}\) block such that it attains acceleration of \(5 \mathrm{~m} / \mathrm{s}^2\). (Assume, acceleration due to gravity, \(\left.g=10 \mathrm{~m} / \mathrm{s}^2.\right)\)
- A \(6.4 \mathrm{~N}\)
- B \(7.1 \mathrm{~N}\)
- C \(6.0 \mathrm{~N}\)
- D \(7.8 \mathrm{~N}\)
Answer & Solution
Correct Answer
(A) \(6.4 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Given, acceleration of block, \(a=5 \mathrm{~m} / \mathrm{s}^2\) and coefficient of friction between two blocks and table, \(\mu=01\) \( \text { Free body diagram for } 0.8 \mathrm{~kg} \text { block. } \) For \(0.8 \mathrm{~kg}\) block, friction force due to…
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