TS EAMCET · Physics · Wave Optics
In a double-slit experiment performed in air the angular width of a fringe is found to be \(0.15^{\circ}\) on a screen placed \(80 \mathrm{~cm}\) away. The wavelength of light used is \(490 \mathrm{~nm}\). The angular width of the fringe if the entire apparatus is immersed in medium of refractive index \(\frac{5}{3}\) is
- A \(0.09^{\circ}\)
- B \(0.7^{\circ}\)
- C \(0.9^{\circ}\)
- D \(0.11^{\circ}\)
Answer & Solution
Correct Answer
(A) \(0.09^{\circ}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \theta=\frac{\lambda}{\mathrm{d}} \Rightarrow \theta \propto \lambda \\ & \Rightarrow \quad \frac{\theta_2}{\theta_1}=\frac{\lambda_2}{\lambda_1}=\frac{\lambda}{\mu \cdot \lambda} \\ & \Rightarrow \quad \theta_2=\frac{\theta_1}{\mu}=\frac{0.15^{\circ}}{5}…
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