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TS EAMCET · Physics · Nuclear Physics

The half-life of a radioactive element is \(10 \mathrm{~h}\). The fraction of initial radioactivity of the element that will remain after \(40 \mathrm{~h}\) is

  1. A \(\frac{1}{2}\)
  2. B \(\frac{1}{16}\)
  3. C \(\frac{1}{8}\)
  4. D \(\frac{1}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{16}\)

Step-by-step Solution

Detailed explanation

After 4 half-lifes \(\frac{N_0}{2^4}=\frac{N_0}{16}\)