TS EAMCET · Physics · Gravitation
If the acceleration due to gravity \(g\) doubles and the radius of earth becomes half that of the present value, then the value of escape velocity is (Assume, \(g=10 \mathrm{~m} / \mathrm{s}^2\) and radius of earth, \(R=6400 \mathrm{~km}\) )
- A \(12 \mathrm{~km} / \mathrm{s}\)
- B \(16 \sqrt{2} \mathrm{~km} / \mathrm{s}\)
- C \(8 \sqrt{2} \mathrm{~km} / \mathrm{s}\)
- D \(4 \sqrt{2} \mathrm{~km} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(12 \mathrm{~km} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
Given, radius of earth, \(R_e=6400 \mathrm{~km}=6.4 \times 10^6 \mathrm{~m}\) and acceleration of gravity, \(g=10 \mathrm{~m} / \mathrm{s}^2\) \(\therefore\) Escape velocity of the surface of earth,…
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