TS EAMCET · Physics · Magnetic Effects of Current
Magnetic field induction at the centre of a circular coil of radius \(5 \mathrm{~cm}\) and carrying a current \(0.9 \mathrm{~A}\) is (in SI units) \(\left(\varepsilon_0=\right.\) absolute permittivity of air in SI units, velocity of light \(=3 \times 10^8 \mathrm{~ms}^{-1}\) )
- A \(\frac{1}{\varepsilon_0 10^{16}}\)
- B \(\frac{10^{16}}{\varepsilon_0}\)
- C \(\frac{\varepsilon_0}{10^{16}}\)
- D \(10^{16} \varepsilon_0\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{\varepsilon_0 10^{16}}\)
Step-by-step Solution
Detailed explanation
Magnetic field induction at the centre of circular coil, \(B=\frac{\mu_0 J}{2 r}\)....(i) \(\begin{aligned} & c^2=\frac{1}{\mu_0 \varepsilon_0} \\ & \therefore \quad \mu_0=\frac{1}{\varepsilon_0 c^2} \\ & \end{aligned}\) So, from Eq. (i), we get…
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