TS EAMCET · Physics · Kinetic Theory of Gases
If a gas has \(n\) degrees of freedom, then the ratio of \(\frac{C_p}{C_V}\) is
- A \(\frac{n+2}{n}\)
- B \(\frac{2 n+1}{n}\)
- C \(\frac{n+2}{2 n}\)
- D \(\frac{n+4}{2 n}\)
Answer & Solution
Correct Answer
(A) \(\frac{n+2}{n}\)
Step-by-step Solution
Detailed explanation
For a gas with \(n\) degree of freedom, \(\begin{aligned} C_p & =\left(\frac{n}{2}+1\right) \cdot R \quad \text { and } C_V=\frac{n}{2} R \\ \Rightarrow \quad \frac{C_p}{C_V} & =\frac{\left(\frac{n}{2}+1\right) R}{\frac{n}{2} \cdot R}=\left(\frac{n+2}{n}\right) \end{aligned}\)
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