TS EAMCET · Physics · Rotational Motion
The distance between Sun and Earth is \(1.6 \times 10^{11} \mathrm{~m}\) and the radius of Earth is \(6.4 \times 10^6 \mathrm{~m}\). The ratio of the angular momentum of Earth around the Sun to the angular momentum around its own axis is approximately (Assume Earth as a solid sphere with uniform mass density and rotates around the Sun in a circular path.)
- A \(2.0 \times 10^2\)
- B \(5.1 \times 10^8\)
- C \(4.3 \times 10^6\)
- D \(8.7 \times 10^{12}\)
Answer & Solution
Correct Answer
(C) \(4.3 \times 10^6\)
Step-by-step Solution
Detailed explanation
Given, the distance between the Sun and Earth, \(r_1=1.6 \times 10^{11} \mathrm{~m}\) Radius of earth, \(R_e=6.4 \times 10^6 \mathrm{~m}\) Angular momentum of Earth around the Sun, \(L_1=M_e v_1 r_1=M_e \cdot \frac{2 \pi r_1}{T_1} \cdot r_1\)…
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