TS EAMCET · Physics · Dual Nature of Matter
The de Broglie wavelength of an electron accelerated between two plates having a potential difference of 900 \(\mathrm{V}\) is neariy.
- A \(0.015nm\)
- B \(0.01nm\)
- C \(0.02mm\)
- D \(0.04nm\)
Answer & Solution
Correct Answer
(D) \(0.04nm\)
Step-by-step Solution
Detailed explanation
de Broglie wavelength is given by \(\begin{aligned} & \lambda=\frac{12.27 \times 10^{-10}}{\sqrt{\mathrm{V}}} \\ & =\frac{12.27 \times 10^{-10}}{\sqrt{900}} \\ & =\frac{12.27 \times 10^{-10}}{30} \\ & =0.04 \mathrm{~nm} \end{aligned}\)
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