TS EAMCET · Physics · Communication System
For an amplitude modulated wave, the maximum amplitude is found to be \(10 \mathrm{~V}\) while the minimum amplitude is found to be \(4 \mathrm{~V}\). The modulation index is
- A \(\frac{2}{5}\)
- B \(\frac{2}{3}\)
- C \(\frac{3}{7}\)
- D \(\frac{4}{7}\)
Answer & Solution
Correct Answer
(C) \(\frac{3}{7}\)
Step-by-step Solution
Detailed explanation
Given that, maximum amplitude, \(A_{\max }=10 \mathrm{~V}\) Minimum amplitude, \(A_{\min }=4 \mathrm{~V}\) Now, modulation index, \(\mu=\frac{A_{\max }-A_{\min }}{A_{\max }+A_{\min }}=\frac{10-4}{10+4}=\frac{6}{14}=\frac{3}{7}\)
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