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TS EAMCET · Physics · Thermodynamics

An office room contains about 2000 moles of air. The change in the internal energy of this much air when it is cooled from \(34^{\circ} \mathrm{C}\) to \(24^{\circ} \mathrm{C}\) at a constant pressure of \(1.0 \mathrm{~atm}\) is [Use \(\gamma_{\text {air }}=1.4\) and whiversal gas constant \(=8.314 \mathrm{~J} / \mathrm{mol}-\mathrm{K}]\)

  1. A \(-1.9 \times 10^5 \mathrm{~J}\)
  2. B \(+1.9 \times 10^5 \mathrm{~J}\)
  3. C \(-4.2 \times 10^5 \mathrm{~J}\)
  4. D \(+0.7 \times 10^5 \mathrm{~J}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-4.2 \times 10^5 \mathrm{~J}\)

Step-by-step Solution

Detailed explanation

Given, Number of moles of air in room \((n)=2000=2 \times 10^3\) Temperature difference \((\mathrm{dT})=24-34=-10^{\circ} \mathrm{C}\) We know that,…
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