TS EAMCET · Physics · Oscillations
The displacement of a particle executing simple harmonic motion is given by \(x=2 \cos (t)\) where \(t\) is the time in seconds then the time period of the particle is
- A \(\pi\) second
- B \(2 \pi\) second
- C \(3 \pi\) second
- D \(0.5 \pi\) second
Answer & Solution
Correct Answer
(B) \(2 \pi\) second
Step-by-step Solution
Detailed explanation
The simple harmonic motion is given by \[ x=2 \cos t \] Compaire with \(\mathrm{x}=\mathrm{A} \cos \omega \mathrm{t}\) \[ \begin{aligned} & \omega=1 \\ & \frac{2 \pi}{T}=1 \end{aligned} \] Time period of the particle, \(\mathrm{T}=2 \pi\) Second.
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