TS EAMCET · Physics · Current Electricity
The resistivity of a metal is \(1 \times 10^{-8} \Omega \mathrm{m}\). If it contains \(9 \times 10^{28}\) electrons per \(\mathrm{m}^3\) then the relaxation time of electrons inside the metal is nearly (electron mass \(=9 \times 10^{-31} \mathrm{~kg}\) )
- A \(4 \times 10^{-14} \mathrm{~s}\)
- B \(7 \times 10^{-14} \mathrm{~s}\)
- C \(1.0 \times 10^{-14} \mathrm{~s}\)
- D \(9 \times 10^{-14} \mathrm{~s}\)
Answer & Solution
Correct Answer
(A) \(4 \times 10^{-14} \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
We have the expression for electrical resistivity is given by \(\rho=\frac{m}{\mathrm{ne}^2 \tau}\)…
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