TS EAMCET · Physics · Electrostatics

The fringe widths are found to be $ω_{1}$ and $ω_{2}$ respectively if a Young's double slit experiment is performed in medium of refractive index $n_{1}$ and $n_{2}$ respectively. The correct statement is

A $ω_{1} > ω_{2}$ if $n_{1} > n_{2}$
B $ω_{1} > ω_{2}$ if $n_{1} < n_{2}$
C $ω_{1} = ω_{2}$ if $n_{1} < n_{2}$
D $\frac{ω_{1}}{ω_{2}} = \frac{n_{1}}{n_{2}}$

Verified Solution

Answer & Solution

Correct Answer

(B) $ω_{1} > ω_{2}$ if $n_{1} < n_{2}$

Step-by-step Solution

Detailed explanation

Fringe width of Y.D.S.E. in a medium is given by, ω=Dλdn For a particular Y.D.S.E. set up and light, D, d & λ remains constant, therefore ω∝1n So, we can conclude, if n2>n1, ω1>ω2.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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The fringe widths are found to be ω1 and ω2 respectively if a Young's double slit experiment is performed in medium of refractive index n1 and n2 respectively. The correct statement is

Step-by-step Solution

The fringe widths are found to be $ω_{1}$ and $ω_{2}$ respectively if a Young's double slit experiment is performed in medium of refractive index $n_{1}$ and $n_{2}$ respectively. The correct statement is