TS EAMCET · Physics · Motion In One Dimension
The initial and final velocities of a body projected vertically from the ground are \(20 \mathrm{~ms}^{-1}\) and \(18 \mathrm{~ms}^{-1}\) respectively. The maximum height reached by the body is (Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A 20 m
- B 16.2 m
- C 19 m
- D 18.1 m
Answer & Solution
Correct Answer
(A) 20 m
Step-by-step Solution
Detailed explanation
\(v^2 = u^2 + 2as\) \(0^2 = (20 \mathrm{~ms}^{-1})^2 + 2(-10 \mathrm{~ms}^{-2})h_{max}\) \(0 = 400 - 20h_{max}\) \(20h_{max} = 400\) \(h_{max} = 20 \mathrm{~m}\)
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