TS EAMCET · Physics · Magnetic Effects of Current
For a wire, as shown in the figure, carrying a current of \(10 \mathrm{~A}\), then the magnetic induction field at the point \(O\) is [talse, \(\mu_0=4 \pi \times 10^{-7} \mathrm{H} / \mathrm{m}\) ]
- A \(2 \times 10^4 \mathrm{~T}\)
- B \(4 \times 10^4 \mathrm{~T}\)
- C \(10 \times 10^4 \mathrm{~T}\)
- D \(4 \pi \times 10^4 \mathrm{~T}\)
Answer & Solution
Correct Answer
(B) \(4 \times 10^4 \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
Magnetic field due to a Iong current carrying wire at one end is given by \(B=\frac{\mu_0 i}{4 \pi d}\). (where, \(i=\) current and \(d=\) distance from the wire) For both the wire, \[ i=10 \mathrm{~A}, d=\frac{1}{2} \times 10^{-2} \mathrm{~m} \] Magnetic field due to one wire,…
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