TS EAMCET · Physics · Thermal Properties of Matter
How much thermal energy is required to change a \(40 \mathrm{~g}\) ice cube from solid at \(-10^{\circ} \mathrm{C}\) to steam at \(110^{\circ} \mathrm{C}\) ? [Assume, latent heat of fusion for water \(=80 \mathrm{kcal} / \mathrm{kg}\), specific heat of water \(=1 \mathrm{kcal} / \mathrm{kg}^{\circ} \mathrm{C}\), specific heat of ice \(=0.5 \mathrm{kcal} / \mathrm{kg}^{\circ} \mathrm{C}\), specific heat of steam \(=0.48 \mathrm{kcal} / \mathrm{kg}^{\circ} \mathrm{C}\), latent heat of vaporisation of water \(\left.=540 \mathrm{kcal} / \mathrm{kg}^{\circ} \mathrm{C}\right]\)
- A \(29.192 \mathrm{kcal}\)
- B \(40.288 \mathrm{kcal}\)
- C \(35.188 \mathrm{kcal}\)
- D \(30.188 \mathrm{kcal}\)
Answer & Solution
Correct Answer
(A) \(29.192 \mathrm{kcal}\)
Step-by-step Solution
Detailed explanation
Following changes occur in given conversion process So, required thermal energy…
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