TS EAMCET · Physics · Rotational Motion
Moment of inertia of a body about an axis is \(4 \mathrm{~kg}-\mathrm{m}^2\). The body is initially at rest and a torque of \(8 \mathrm{~N}\)-m starts acting on it along the same axis. Work done by the torque in \(20 \mathrm{~s}\), in joules, is
- A \(40\)
- B \(640\)
- C \(2560\)
- D \(3200\)
Answer & Solution
Correct Answer
(D) \(3200\)
Step-by-step Solution
Detailed explanation
Given, \(I=4 \mathrm{~kg}-\mathrm{m}^2, \tau=8 \mathrm{~N}-\mathrm{m}\) and \(t=20 \mathrm{~s}\)…
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