TS EAMCET · Physics · Units and Dimensions
The surface tension of 70 dynes \(/ \mathrm{cm}\) is equal to
- A \(70 \mathrm{~N} / \mathrm{m}\)
- B \(70 \times 10^{-3} \mathrm{~N} / \mathrm{m}\)
- C \(7 \times 10^2 \mathrm{~N} / \mathrm{m}\)
- D \(7 \times 10^3 \mathrm{~N} / \mathrm{m}\)
Answer & Solution
Correct Answer
(B) \(70 \times 10^{-3} \mathrm{~N} / \mathrm{m}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \text { Surface tension } & =70 \frac{\text { dynes }}{\mathrm{cm}}=70 \times \frac{10^{-5}}{10^{-2}} \mathrm{~N} / \mathrm{m} \\ & =70 \times 10^{-3} \mathrm{~N} / \mathrm{m}\end{aligned}\)
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