TS EAMCET · Physics · Alternating Current
A capacitance of \(\left(\frac{10^{-3}}{2 \pi}\right) \mathrm{F}\) and an inductance of \(\left(\frac{100}{\pi}\right) \mathrm{mH}\) and a resistance of \(10 \Omega\) are connected in series with an AC voltage source of \(220 \mathrm{~V}, 50 \mathrm{~Hz}\). The phase angle of the circuit is
- A \(60^{\circ}\)
- B \(30^{\circ}\)
- C \(45^{\circ}\)
- D \(90^{\circ}\)
Answer & Solution
Correct Answer
(C) \(45^{\circ}\)
Step-by-step Solution
Detailed explanation
Capacitance, \(C=\frac{10^{-3}}{2 \pi} \mathrm{F}\) Inductance, \(L=\left(\frac{100}{\pi}\right) \mathrm{mH}=\frac{100}{\pi} \times 10^{-3} \mathrm{H}\) Resistance, \(R=10 \Omega\) Voltage of source \(=220 \mathrm{volt}\) Frequency of source, \(f=50 \mathrm{~Hz}\) Phase angle…
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