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TS EAMCET · Physics · Magnetic Effects of Current

Two infinitely long straight wires \(A\) and \(B\), each carrying current \(I\) are placed on \(x\) and \(y\)-axis, respectively. The current in wires \(A\) and \(B\) flow along \(-\hat{\mathbf{i}}\) and \(\hat{\mathbf{j}}\) directions respectively. The force on a charged particle having charge \(q\), moving from position, \(\mathbf{r}=d(\hat{\mathbf{i}}+\hat{\mathbf{j}})\) with velocity \(\mathbf{v}=\hat{v}\) is

  1. A \(\frac{\mu_0 f v^{\prime}}{2 \pi \sigma^{\prime}} \hat{\mathbf{j}}\)
  2. B \(\frac{\mu_0 f q v}{\pi \sigma^{\prime}} \hat{\mathbf{j}}\)
  3. C \(\frac{\mu_0 f Q v}{\sqrt{2} \pi \phi} \hat{\mathbf{k}}\)
  4. D 0
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Answer & Solution

Correct Answer

(B) \(\frac{\mu_0 f q v}{\pi \sigma^{\prime}} \hat{\mathbf{j}}\)

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Detailed explanation

The given situation for two current carrying wires are shown in the figures. Position vector of charge particle, \( \mathbf{r}=d(\hat{\mathbf{i}}+\hat{\mathbf{j}})=d \hat{\mathbf{i}}+d \hat{\mathbf{j}} \) The magnetic field intensity due to the wire along \(-\hat{\mathbf{i}}\)…
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