TS EAMCET · Physics · Mathematics in Physics
In five successive measurements, the mass of a ball is measured to be \(2.61 \mathrm{~g}, 2.58 \mathrm{~g}\), \(2.40 \mathrm{~g}, 2.73 \mathrm{~g}\) and \(2.80 \mathrm{~g}\). The absolute error in the measurement is
- A \(0.09 \mathrm{~g}\)
- B \(0.07 \mathrm{~g}\)
- C \(0.11 \mathrm{~g}\)
- D \(0.13 \mathrm{~g}\)
Answer & Solution
Correct Answer
(C) \(0.11 \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
Mean mass of the ball is \(\bar{M}=\frac{m_1+m_2+m_3+m_4+m_5}{5}\) \(=\frac{2.61+2.58+2.40+2.73+2.80}{5}\) \(\bar{M}=2.624 \mathrm{~g} \simeq 2.62 \mathrm{~g}\) \(\therefore\) Mean absolute error,…
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