TS EAMCET · Physics · Magnetic Effects of Current
Two short magnets of equal dipole moments \(M\) are fastened perpendicularly at their centres which lies at origin. Let two magnets lie along \(X\)-axis and \(Y\)-axis, respectively. The magnitude of the magnetic field at a distance \(R\) from the centre on the \(Y\)-axis is \(\frac{\mu_0}{4 \pi} \frac{M_0}{R^3}\). Assuming, \(R>>l\) (magnet length), the magnitude of \(M\) is
- A \(\frac{M_0}{2 \sqrt{2}}\)
- B \(\frac{M_0}{2}\)
- C \(\frac{M_0}{\sqrt{5}}\)
- D \(\frac{M_0}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(C) \(\frac{M_0}{\sqrt{5}}\)
Step-by-step Solution
Detailed explanation
Two magnet are joined as shown in figure. The magnetic field at point \(P\) due to magnet \(M_1\) is on axial line, while that due to \(M_2\) is on equatorial line. So, net magnetic field at a point \(P\) at a distance \(R\) on \(Y\)-axis,…
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