TS EAMCET · Physics · Alternating Current
In a circuit \(L, C\) and \(R\) are connected in series with an alternating voltage source of frequency \(f\). When current in the circuit leads the voltage by \(45^{\circ}\), the value of \(C\) is
- A \(\frac{1}{2 \pi f(2 \pi f L+R)}\)
- B \(\frac{1}{2 \pi f(2 \pi f R+L)}\)
- C \(\frac{2}{2 \pi f(R+L)}\)
- D \(\frac{2}{2 \pi f\left(R+\frac{1}{L}\right)}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2 \pi f(2 \pi f L+R)}\)
Step-by-step Solution
Detailed explanation
Current leads the voltage by \(45^{\circ}\) \[ \begin{array}{rlrl} & \therefore & \phi & =45^{\circ} \\ \text { Since, }, & \tan \phi & =\frac{X_C-X_L}{R} \\ \Rightarrow & 1 & =\frac{X_C-X_L}{R} \end{array} \]…
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