TS EAMCET · Physics · Dual Nature of Matter
A radiation of energy \(E\) falls on a perfectly reflecting surface. The momentum transferred to the surface is (let \(c \equiv\) speed of light)
- A \(\frac{E}{C}\)
- B \(\frac{2 E}{c}\)
- C EC
- D \(\frac{E}{c^2}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 E}{c}\)
Step-by-step Solution
Detailed explanation
The momentum carried by a photon of energy \(E\) and wavelength \(\lambda\) is \(p=\frac{h}{\lambda}=\frac{h c}{\lambda c}=\frac{h c}{\lambda} \times \frac{1}{c}=E \times \frac{1}{c}=\frac{E}{c} \quad\left[\because \frac{h c}{\lambda}=E\right]\) where, \(h=\) Planck's constant.…
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