TS EAMCET · Physics · Magnetic Properties of Matter
If two identical bar magnets, each of length \(l\), pole strength \(m\) and magnetic moment \(M\) are placed perpendicular to each other with their unlike poles in contact, the magnetic moment of the combination is
- A \(\frac{M}{\sqrt{2}}\)
- B \(\operatorname{lm}(\sqrt{2})\)
- C \(2 \operatorname{lm}(\sqrt{2})\)
- D \(2 M\)
Answer & Solution
Correct Answer
(B) \(\operatorname{lm}(\sqrt{2})\)
Step-by-step Solution
Detailed explanation
When magnets are placed perpendicular to each other then, Resultant magnetic moment \(M^{\prime}=\sqrt{M_1^2+M_2^2}\) Here, \(M_1=M_2=M\) So, \(M^{\prime}=M \sqrt{2}=m l \sqrt{2}\) \([\because M=m l]\)
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