TS EAMCET · Physics · Current Electricity
Consider a wire of length \(L\) with a resistance of \(5 \Omega\). Applying an external force, the wire is elongated such that its length becomes \(3 L\). Assuming, the resistivity and density of the material is unchanged, the resistance of the elongated wire is
- A \(40 \Omega\)
- B \(45 \Omega\)
- C \(50 \Omega\)
- D \(48 \Omega\)
Answer & Solution
Correct Answer
(B) \(45 \Omega\)
Step-by-step Solution
Detailed explanation
\(R=\frac{\rho \sigma L^2}{m}\)Resistance of wire of length \(L, R=5 \Omega\) If area of cross-section be \(A\), then \( R=\rho \frac{L}{A} \quad(\rho=\text { resistivity of the wire }) \) After applying external force new length becomes, \(L^{\prime}=3 L\)…
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