TS EAMCET · Physics · Dual Nature of Matter
If Planck's constant is \(6.63 \times 10^{-34} \mathrm{Js}\), then the slope of a graph drawn between cut off voltage and frequency of incident light in a photoelectric experiment is
- A \(4.14 \times 10^{-15} \mathrm{Vs}\)
- B \(19.776 \times 10^{-15} \mathrm{Vs}\)
- C \(2.198 \times 10^{-15} \mathrm{Vs}\)
- D \(1.337 \times 10^{-15} \mathrm{Vs}\)
Answer & Solution
Correct Answer
(A) \(4.14 \times 10^{-15} \mathrm{Vs}\)
Step-by-step Solution
Detailed explanation
Energy \(\mathbf{E}=\mathbf{h v}=\mathbf{e v}\) So slope of graph drawn between cut-off voltage ( v ) and frequency of incident light in a photoelectric experiment…
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