TS EAMCET · Physics · Alternating Current
For an \(R-L-C\) circuit, driven with voltage of amplitude \(V_m\) and frequency \(\omega_0=\frac{1}{\sqrt{L C}}\), the current exhibits resonance. The quality factor \(Q\) is
- A \(\frac{\omega_0 R}{L}\)
- B \(\frac{R}{\omega_0 C}\)
- C \(\frac{C R}{\omega_0}\)
- D \(\frac{\omega_0 L}{R}\)
Answer & Solution
Correct Answer
(D) \(\frac{\omega_0 L}{R}\)
Step-by-step Solution
Detailed explanation
The quality factor of a \(R-L-C\) circuit is \(Q=\frac{1}{R} \sqrt{\frac{L}{C}}\) At resonance, \(X_L=X_C\) \(\Rightarrow \omega_0 L=\frac{1}{\omega_0 C} \Rightarrow \omega_0=\frac{1}{\sqrt{L C}} \text { or } \sqrt{\frac{L}{C}}=\omega_0 L\)…
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