TS EAMCET · Physics · Capacitance
A parallel plate capacitor with air as dielectric has a capacitance of \(4 \mu \mathrm{~F}\). The space between the plates of the capacitor is completely filled with a material of dielectric constant 5 and charged to a potential of 100 V. The work done to completely remove the dielectric material after the capacitor is disconnected from the battery is
- A 0.1 J
- B 0.5 J
- C 0.6 J
- D 0.4 J
Answer & Solution
Correct Answer
(D) 0.4 J
Step-by-step Solution
Detailed explanation
\(W = \frac{1}{2} C_0 V^2 \kappa (\kappa - 1)\) \(W = \frac{1}{2} (4 \times 10^{-6} \, \mathrm{F}) (100 \, \mathrm{V})^2 (5) (5 - 1)\) \(W = 0.4 \, \mathrm{J}\)
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