TS EAMCET · Physics · Ray Optics
A thin converging lens of focal length \(f=25 \mathrm{~cm}\) forms the image of an object on a screen placed at a distance of \(75 \mathrm{~cm}\) from the lens. The screen is moved closer to the lens by a distance of \(25 \mathrm{~cm}\). The distance through which the object has to be shifted, so that its image on the screen in sharp again is
- A \(37.5 \mathrm{~cm}\)
- B \(16.25 \mathrm{~cm}\)
- C \(12.5 \mathrm{~cm}\)
- D \(13.5 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(C) \(12.5 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
According to the first condition,…
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